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Valid Pair - CodeChef Solution in Java | AskTheCode

Team ATC

Updated: Apr 12, 2021

CodeChef April Long Challenge Solution| Valid Pair (SOCKS1) solution in Java | AskTheCode

 

Problem:

Chef has three socks in his drawer. Each sock has one of 10 possible colours, which are represented by integers between 1 and 10. Specifically, the colours of the socks are A, B, and C.

Chef has to wear two socks which have the same colour. Help Chef find out if that is possible or not.

 

Input:

The first and only line of the input contains three space-separated integers A, B and C.

 

Output:

Print a single line containing the string "YES" if it is possible for Chef to wear two socks with the same colour or "NO" if it is impossible (without quotes).

You may print each character of each string in uppercase or lowercase (for example, the strings "yEs", "yes", "Yes" and "YES" will all be treated as identical).

 

Example Input 1:

5 4 3

 

Example Output 1:

NO

 

Explanation:

Since there are no two socks with the same colour, Chef cannot wear a pair of socks with the same colour.

 

Example Input 1:

5 5 5

 

Example Output 1:

YES

 

Explanation:

Since all three socks have the same colour, Chef can wear a pair of socks with the same colour.

 

Code:

In Java

/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
 public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        int a = input.nextInt();
        int b = input.nextInt();
        int c = input.nextInt();
        System.out.println(solve(a,b,c));
    }

    public static String solve(int a, int b, int c) {
        if (a == b || a == c || b == c) {
            return "Yes";
        } else {
            return "No";
        }
    }
}
 

In C++

#include <iostream>
#include<bits/stdc++.h>
using namespace std;

int main() {
	int a[3],k=0;
	cin>>a[0]>>a[1]>>a[2];
	sort(a,a+3);
	for(int i=0;i<2;i++)
	{
	    if (a[i]==a[i+1])
	    {
	    cout<<"yes"<<endl;
	    k++;
	    break;
	    }
	    
	}
	if (k==0)
	cout<<"No"<<endl;
	
	return 0;
}

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